X has 2 tennis serves a hard serve ans a soft serve. Her hard serve has a 50% chance of being good.?

Question

If her hard serve is good then she has an 80% chance of winning the point. Her soft serve has a 90% chance of being good. If her soft serve is good, she has a 50% chance of winning the point. What is the probability that x wins if she serves hard and then if necessary serves soft? what is the probability that x wins the point if she serves the first serves hard then if necessary her second serve hard?

Answer 1

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Wow.... I hate probability.

Source(s):

Failed at it in 6th grade.

Answer 2

First of all, those percentages won't always translate into X's game. One day she might be getting all her first serves in, another day she might be getting only 1 out of 3 in. What X has to do is work on a serve that has a good amount of spin and goes in almost all the time. Having a second serve with alot of spin is much better than having a little ding serve. X should keep her hard serve.

Like I said before, X shouldn't count on percentages. they vary on whether it is a good or bad day for X and how well the opponent plays.

Answer 3

She has a 40% of winning the point on just one serve: (.5)(.8) = .4

Therefore, there is a 60% chance she will need a second serve. The overall probability of her winning the point is thus:

(.5)(.8) + (.6)(.9)(.5) = .67 or 67%.

Based on this you should be able to figure out the second part.

And you would have got an answer more quickly had this been placed in the mathematics or homework category.

Answer 4

?? i don't think that is a tennis question........ besides, there's no correlation between her serves and how she plays during the point, so.... that's an awful math question

Answer 5

tennislvoer i think this is a math question and not based on real play